The correct option(s) to distinguish nitrate salts of Mn 2+ and Cu 2+ taken separately is (are)

Only Cu 2+ shows the formation of precipitate by passing H 2 S in acidic medium

Cu 2+ / Cu has higher reduction potential than Mn 2+ / Mn (measured under similar conditions)

Only Mn 2+ shows the formation of precipitate by passing H 2 S in faintly basic medium

Chemistry · Practical Inorganic chemistry (Qualitative Analysis)

JEE Advanced 2018 — Paper 2 — Question 19

The correct option(s) to distinguish nitrate salts of $\mathrm{Mn}^{2+}$ and $\mathrm{Cu}^{2+}$ taken separately is (are)

Option A:
$\mathrm{Mn}^{2+}$ shows the characteristic green colour in the flame test
Option B:
$\mathrm{Only}^{\mathrm{Cu}^{2+}}$ shows the formation of precipitate by passing $\mathrm{H}_{2} \mathrm{~S}$ in acidic medium
Correct
Option C:
Only $\mathrm{Mn}^{2+}$ shows the formation of precipitate by passing $\mathrm{H}_{2} \mathrm{~S}$ in faintly basic medium
Option D:
$\mathrm{Cu}^{2+} / \mathrm{Cu}$ has higher reduction potential than $\mathrm{Mn}^{2+} / \mathrm{Mn}$ (measured under similar conditions)
Correct

$\mathrm{Cu}^{2+}$ shows the characteristic green colour in the flame test.

Ksp of $\mathrm{CuS}<\mathrm{Ksp}$ of MnS

\mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}}^{0}>\mathrm{E}_{\mathrm{Mn}^{2+}+\mathrm{Mn}}^{0}

Answer key and solution verified before publishing.

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