The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions, is List-I List-II --- --- (P) Passing H 2 \!\! \!\! S in the presence of N H 4 OH (1) C u 2+ (Q) ( N H 4 ) 2 C O 3 in the presence of N H 4 OH (2) A l 3+ (R) \!\! \!\! N H 4 OH in the presence of N H 4 Cl (3) M n 2+ (S) Passing H 2 \!\! \!\! S in the presence of dilute HCl (4) B a 2+ (5) M g 2+

P rightarrow 3 ; Q rightarrow 4 ; R rightarrow 2 ; S rightarrow 1

P rightarrow 4 ; Q rightarrow 2 ; R rightarrow 3 ; S rightarrow 1

P rightarrow 3 ; Q rightarrow 4 ; R rightarrow 1 ; S rightarrow 5

P rightarrow 5 ; Q rightarrow 3 ; R rightarrow 2 ; S rightarrow 4

Chemistry · Practical Inorganic chemistry (Qualitative Analysis)

JEE Advanced 2025 — Paper 1 — Question 43

The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions, is

List-I	List-II
(P) Passing ${{\text{H}}_{2}}\text{ }\!\!~\!\!\text{ S}$ in the presence of $\text{N}{{\text{H}}_{4}}\text{OH}$	(1) $\text{C}{{\text{u}}^{2+}}$
(Q) ${{\left( \text{N}{{\text{H}}_{4}} \right)}_{2}}\text{C}{{\text{O}}_{3}}$ in the presence of $\text{N}{{\text{H}}_{4}}\text{OH}$	(2) $\text{A}{{\text{l}}^{3+}}$
(R) $\text{ }\!\!~\!\!\text{ N}{{\text{H}}_{4}}\text{OH}$ in the presence of $\text{N}{{\text{H}}_{4}}\text{Cl}$	(3) $\text{M}{{\text{n}}^{2+}}$
(S) Passing ${{\text{H}}_{2}}\text{ }\!\!~\!\!\text{ S}$ in the presence of dilute HCl	(4) $\text{B}{{\text{a}}^{2+}}$
	(5) $\text{M}{{\text{g}}^{2+}}$

Option A:
$\mathrm{P} \rightarrow 3 ; \mathrm{Q} \rightarrow 4 ; \mathrm{R} \rightarrow 2 ; \mathrm{S} \rightarrow 1$
Correct
Option B:
$\mathrm{P} \rightarrow 4 ; \mathrm{Q} \rightarrow 2 ; \mathrm{R} \rightarrow 3 ; \mathrm{S} \rightarrow 1$
Option C:
$\mathrm{P} \rightarrow 3 ; \mathrm{Q} \rightarrow 4 ; \mathrm{R} \rightarrow 1 ; \mathrm{S} \rightarrow 5$
Option D:
$\mathrm{P} \rightarrow 5 ; \mathrm{Q} \rightarrow 3 ; \mathrm{R} \rightarrow 2 ; \mathrm{S} \rightarrow 4$

Answer: A

Step-by-step solution

$\mathrm{Mn}^{+2} \xrightarrow{\mathrm{H}_{2} \mathrm{~S}+\mathrm{NH}_{4} \mathrm{OH}} \underset{\text { Pink/buff ppt. }}{\mathrm{MnS}} \downarrow$ $\mathrm{Ba}^{+2} \xrightarrow{\left(\mathrm{NH}_{4}\right)_{2} \mathrm{CO}_{3}+\mathrm{NH}_{4} \mathrm{OH}} \underset{\text { White ppt. }}{\mathrm{BaCO}_{3} \downarrow}$

$\mathrm{Al}^{+3} \xrightarrow{\mathrm{NH}_{4} \mathrm{Cl}+\mathrm{NH}_{4} \mathrm{OH}} \underset{\text { White ppt. }}{\mathrm{Al}(\mathrm{OH})_{3} \downarrow}$ $\mathrm{Cu}^{+2} \xrightarrow{\mathrm{H}_{2} \mathrm{~S}+\mathrm{HCl}(\text { dil. })} \underset{\text { Black ppt. }}{\mathrm{CuS} \downarrow}$

Answer key and solution verified before publishing.

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Exam: JEE Advanced 2025
Paper: Paper 1
Subject: Chemistry
Chapter: Practical Inorganic chemistry (Qualitative Analysis)
Topic: Identification of Cations (Groups 1 to 3)