The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO 3 to a compound with the highest oxidation state of sulphur is \ \ \ \ ( . Given data : Molar mass of water .=18 g mol -1 )

Chemistry · p-Block Elements (Group 15-18)

JEE Advanced 2019 — Paper 2 — Question 19

The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. $\mathrm{HNO}_{3}$ to a compound with the highest oxidation state of sulphur is $\_\_\_\_$ $\left(\right.$ Given data : Molar mass of water $\left.=18 \mathrm{~g} \mathrm{~mol}^{-1}\right)$

Answer: 288

Numerical answer — enter this value.

Step-by-step solution

$\mathrm{S}_{8}+48 \mathrm{HNO}_{3} \square \longleftrightarrow 8 \mathrm{H}_{2} \mathrm{SO}_{4}+48 \mathrm{NO}_{2}+16 \mathrm{H}_{2} \mathrm{O}$

Mass of $\mathrm{H}_{2} \mathrm{O}=18 \times 16=288$ gram

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Exam: JEE Advanced 2019
Paper: Paper 2
Subject: Chemistry
Chapter: p-Block Elements (Group 15-18)
Topic: Compounds of Sulphur - preparation and properties

With reference to aqua regia, choose the correct option(s)

Answer: 288

Step-by-step solution

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