Chemistry · Redox Reactions

JEE Advanced 2025 — Paper 1 — Question 33

One of the products formed from the reaction of permanganate ion with iodide ion in neutral aqueous medium is

  1. Option A:

    I2\mathrm{I}_{2}

  2. Option B:

    IO3−\mathrm{IO}_{3}^{-}

    Correct
  3. Option C:

    IO4−\mathrm{IO}_{4}^{-}

  4. Option D:

    IO2−\mathrm{IO}_{2}^{-}

Answer: B

Step-by-step solution

I−+2MnO4−+H2O→ Neutral solution 2MnO2+IO3−+2OH−\mathrm{I}^{-}+2 \mathrm{MnO}_{4}^{-}+\mathrm{H}_{2} \mathrm{O} \xrightarrow{\text { Neutral solution }} 2 \mathrm{MnO}_{2}+\mathrm{IO}_{3}^{-}+2 \mathrm{OH}^{-}

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2025
Paper
Paper 1
Subject
Chemistry
Chapter
Redox Reactions
Topic
Types of Redox Reactions & Balancing of Redox Reactions
One of the products formed from the reaction of permanganate ion with… | JEE Advanced 2025 PYQ with Solution · DhiX AI