Chemistry · p-Block Elements (Group 15-18)

JEE Advanced 2023 — Paper 1 — Question 43

Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their products given in List-II

and choose the correct option.

LIST-ILIST-II
P) P2O3+3H2O→\mathrm{P}_{2} \mathrm{O}_{3}+3 \mathrm{H}_{2} \mathrm{O} \rightarrow(1)P(O)(OCH3)Cl2(1) \mathrm{P}(\mathrm{O})\left(\mathrm{OCH}_{3}\right) \mathrm{Cl}_{2}
Q) P4+3NaOH+3H2O→\mathrm{P}_{4}+3 \mathrm{NaOH}+3 \mathrm{H}_{2} \mathrm{O} \rightarrow(2)H3PO3(2) \mathrm{H}_{3} \mathrm{PO}_{3}
R) (R)PCl5+CH3COOH→(\mathrm{R}) \mathrm{PCl}_{5}+\mathrm{CH}_{3} \mathrm{COOH} \rightarrow(3)PH3(3) \mathrm{PH}_{3}
S) ( S)H3PO2+2H2O+4AgNO3→(\mathrm{~S}) \mathrm{H}_{3} \mathrm{PO}_{2}+2 \mathrm{H}_{2} \mathrm{O}+4 \mathrm{AgNO}_{3} \rightarrow(4)POCl3(4) \mathrm{POCl}_{3}
(5)H3PO4(5) \mathrm{H}_{3} \mathrm{PO}_{4}
  1. Option A:

    P→2;Q→3;R→1\mathrm{P} \rightarrow 2 ; \mathrm{Q} \rightarrow 3 ; \mathrm{R} \rightarrow 1; S→5\mathrm{S} \rightarrow 5

  2. Option B:

    P→3\mathrm{P} \rightarrow 3; Q →5\rightarrow 5; R →4\rightarrow 4; S→2\mathrm{S} \rightarrow 2

  3. Option C:

    P→5\mathrm{P} \rightarrow 5; Q →2;R→1\rightarrow 2 ; \mathrm{R} \rightarrow 1; S→3\mathrm{S} \rightarrow 3

  4. Option D:

    P→2;Q→3;R→4\mathrm{P} \rightarrow 2 ; \mathrm{Q} \rightarrow 3 ; \mathrm{R} \rightarrow 4; S→5\mathrm{S} \rightarrow 5

    Correct

Answer: D

Step-by-step solution

P2O3+3H2O⟶2H3PO3\mathrm{P}_{2} \mathrm{O}_{3}+3 \mathrm{H}_{2} \mathrm{O} \longrightarrow 2 \mathrm{H}_{3} \mathrm{PO}_{3} P4+3NaOH+3H2O⟶PH3+3NaH2PO2\mathrm{P}_{4}+3 \mathrm{NaOH}+3 \mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{PH}_{3}+3 \mathrm{NaH}_{2} \mathrm{PO}_{2} PCl5+CH3COOH⟶CH3COCl+POCl3+HCl\mathrm{PCl}_{5}+\mathrm{CH}_{3} \mathrm{COOH} \longrightarrow \mathrm{CH}_{3} \mathrm{COCl}+\mathrm{POCl}_{3}+\mathrm{HCl} H3PO2+2H2O+4AgNO3⟶H3PO4+4Ag+4HNO3\mathrm{H}_{3} \mathrm{PO}_{2}+2 \mathrm{H}_{2} \mathrm{O}+4 \mathrm{AgNO}_{3} \longrightarrow \mathrm{H}_{3} \mathrm{PO}_{4}+4 \mathrm{Ag}+4 \mathrm{HNO}_{3} P→2,Q→3,R→4, S→5\mathrm{P} \rightarrow 2, \mathrm{Q} \rightarrow 3, \mathrm{R} \rightarrow 4, \mathrm{~S} \rightarrow 5

Answer key and solution verified before publishing.

Practise p-Block Elements (Group 15-18)

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Exam
JEE Advanced 2023
Paper
Paper 1
Subject
Chemistry
Chapter
p-Block Elements (Group 15-18)
Topic
Compounds of other Group 15 elements - preparation and properties
Match the reactions (in the given stoichiometry of the reactants) in… | JEE Advanced 2023 PYQ with Solution · DhiX AI