Mathematics · Sequence and Series

JEE Advanced 2019 — Paper 1 — Question 45

Let AP(a;d)\mathrm{AP}(\mathrm{a} ; \mathrm{d}) denote the set of all the terms of an infinite arithmetic progression with first term a and common

difference d>0\mathrm{d}>0. If AP(1;3)∩AP⁡(2;5)∩AP(3;7)=AP(a;d)\mathrm{AP}(1 ; 3) \cap \operatorname{AP}(2 ; 5) \cap \mathrm{AP}(3 ; 7)=\mathrm{AP}(\mathrm{a} ; \mathrm{d}) then a+d\mathrm{a}+\mathrm{d} equals ____\_\_\_\_

Answer: 157

Numerical answer — enter this value.

Step-by-step solution

AP⁡(1,3)≡{1,4,7,10,…}=.{n/n=3k+1,k∈W}\operatorname{AP}(1,3) \equiv\{1,4,7,10, \ldots\}=.\{n / n=3 k+1, k \in W\}

AP⁡(2,5)≡{2,7,12,…}=.{n/n=5k+2,k∈W}\operatorname{AP}(2,5) \equiv\{2,7,12, \ldots\}=.\{n / n=5 k+2, k \in W\}

AP⁡(3,7)≡{3,10,17,…}={n/n=7k+3,k∈W}\operatorname{AP}(3,7) \equiv\{3,10,17, \ldots\}=\{n / n=7 k+3, k \in W\}

Let common term is M

M≡1( mod 3),M≡2( mod 5),M≡3( mod 7)M \equiv 1(\bmod 3), M \equiv 2(\bmod 5), M \equiv 3(\bmod 7)

⇒M≡52( mod 105)\Rightarrow \quad \mathrm{M} \equiv 52(\bmod 105)

so a=52,d=105\quad a=52, d=105 and a+d=157a+d=157

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2019
Paper
Paper 1
Subject
Mathematics
Chapter
Sequence and Series
Topic
Arithmetic Progression
Let AP ( a ; d ) denote the set of all the terms of an infinite… | JEE Advanced 2019 PYQ with Solution · DhiX AI