Mathematics · Permutations and Combinations

JEE Advanced 2021 — Paper 2 — Question 18

Let

S1={(i,j,k):i,j,k∈{1,2,…,10}},S_{1} = \{(i,j,k) : i,j,k \in \{1,2,\ldots,10\}\}, S2={(i,j):1≤i<j+2≤10,  i,j∈{1,2,…,10}},S_{2} = \{(i,j) : 1 \leq i < j+2 \leq 10, \; i,j \in \{1,2,\ldots,10\}\}, S3={(i,j,k,l):1≤i<j<k<l,  i,j,k,l∈{1,2,…,10}},S_{3} = \{(i,j,k,l) : 1 \leq i < j < k < l, \; i,j,k,l \in \{1,2,\ldots,10\}\},

and

S4={(i,j,k,l):i,j,k,l  are   distinct   elements   in   {1,2,…,10}}.S_{4} = \{(i,j,k,l) : i,j,k,l \; \text{are\; distinct\; elements\; in\; } \{1,2,\ldots,10\}\}.

If the total number of elements in the set SrS_{r} is nrn_{r}, r=1,2,3,4r = 1,2,3,4, then which of the following statements is (are) \textbf{TRUE}?

  1. Option A:

    n1=1000n_{1}=1000

    Correct
  2. Option B:

    n2=44\mathrm{n}_{2}=44

    Correct
  3. Option C:

    n3=220n_{3}=220

  4. Option D:

    n412=420\frac{\mathrm{n}_{4}}{12}=420

    Correct

Answer: A, B, D

Step-by-step solution

n1=10×10×10=103\mathrm{n}_{1}=10 \times 10 \times 10=10^{3}

n2=8C2+28C1=44\mathrm{n}_{2}={ }^{8} \mathrm{C}_{2}+2{ }^{8} \mathrm{C}_{1}=44

n3=10C4=210\mathrm{n}_{3}={ }^{10} \mathrm{C}_{4}=210

n4=10P4=5040\mathrm{n}_{4}={ }^{10} \mathrm{P}_{4}=5040

n412=420\frac{\mathrm{n}_{4}}{12}=420

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2021
Paper
Paper 2
Subject
Mathematics
Chapter
Permutations and Combinations
Topic
Combinations
Let S 1 = \ (i,j,k) : i,j,k in \ 1,2,ldots,10\ \ , S 2 = \ (i,j) : 1… | JEE Advanced 2021 PYQ with Solution · DhiX AI