In the scheme given below, X and Y , respectively, are

Chemistry · Practical Inorganic chemistry (Qualitative Analysis)

JEE Advanced 2023 — Paper 1 — Question 34

In the scheme given below, $\mathbf{X}$ and $\mathbf{Y}$ , respectively, are

Option A:
$\mathrm{CrO}_{4}^{2-}$ and $\mathrm{Br}_{2}$
Option B:
$\mathrm{MnO}_{4}^{2-}$ and $\mathrm{Cl}_{2}$
Option C:
$\mathrm{MnO}_{4}^{-}$ and $\mathrm{Cl}_{2}$
Correct
Option D:
$\mathrm{MnSO}_{4}$ and HOCl

Answer: C

Step-by-step solution

$\underset{(\mathbf{P})}{\mathrm{Mn}(\mathrm{OH})_{2}} \xrightarrow[\mathrm{aq}_{2} \cdot \mathrm{H}_{2} \mathrm{SO}_{4}]{\mathrm{PbO}_{2} \text { (excess) }} \underset{\text { (x) }}{\mathrm{HMnO}_{4}}$ (purple) $^{(\mathrm{P}}$ ) $\underset{(\mathbf{Q})}{\mathrm{NaCl}} \xrightarrow[\substack{\text { conc. } \mathrm{H}_{2} \mathrm{SO}_{2} (\text { warm })}]{\mathrm{MnO}\left(\mathrm{OH}_{4}\right.} \underset{\text { (Y) }}{\mathrm{Cl}_{2}}$ $\mathrm{Cl}_{2}+\mathrm{KI}-$ Starch $\longrightarrow$ Blue colouration

Answer key and solution verified before publishing.

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Exam: JEE Advanced 2023
Paper: Paper 1
Subject: Chemistry
Chapter: Practical Inorganic chemistry (Qualitative Analysis)
Topic: Identification of Anions