In the following circuit C 1 =12 μ F , C 2 = C 3 =4 μ F and C 4 = C 5 =2 μ F . The charge stored in C 3 is μ C .

Physics · Capacitors and R-C Circuits

JEE Advanced 2022 — Paper 1 — Question 21

In the following circuit $\mathrm{C}_{1}=12 \mu \mathrm{~F}, \mathrm{C}_{2}=\mathrm{C}_{3}=4 \mu \mathrm{~F}$ and $\mathrm{C}_{4}=\mathrm{C}_{5}=2$ $\mu \mathrm{F}$ .

The charge stored in $\mathrm{C}_{3}$ is $\mu \mathrm{C}$ .

Answer: 8

Numerical answer — enter this value.

Step-by-step solution

In the loop 1234, $+6-\frac{48}{12}-\frac{q_{3}}{4}=0, \mathrm{q}_{1}=12(6-2)=48 \mu \mathrm{C}$

$\mathrm{q}_{3}=8 \mu \mathrm{C}$

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Exam: JEE Advanced 2022
Paper: Paper 1
Subject: Physics
Chapter: Capacitors and R-C Circuits
Topic: Combination of Capacitors and Circuit Analysis

A medium having dielectric constant K 1 fills the space between the plates of a parallel plate capacitor. The plates have large area, and…

Answer: 8

Step-by-step solution

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