Chemistry · Structure of Atom

JEE Advanced 2019 — Paper 1 — Question 24

In the decay sequence,

92238U→−x190234Th→−x291234 Pa→−x3234Z→−x490230Th{ }_{92}^{238} \mathrm{U} \xrightarrow{-x_{1}}{ }_{90}^{234} \mathrm{Th} \xrightarrow{-x_{2}}{ }_{91}^{234} \mathrm{~Pa} \xrightarrow{-x_{3}}{ }^{234} \mathrm{Z} \xrightarrow{-\mathrm{x}_{4}}{ }_{90}^{230} \mathrm{Th}

x1,x2,x3\mathrm{x}_{1}, \mathrm{x}_{2}, \mathrm{x}_{3} and x4\mathrm{x}_{4} are particles /radiation emitted by the respective isotopes. The correct option(s) is(are)

  1. Option A:

    x3x_{3} is γ\gamma-ray

  2. Option B:

    Z is an isotope of uranium

    Correct
  3. Option C:

    x2\mathrm{x}_{2} is β−\beta^{-}

    Correct
  4. Option D:

    x1x_{1} will deflect towards negatively charged plate

    Correct

Answer: B, C, D

Step-by-step solution

X1=α\mathrm{X}_{1}=\alpha

X2=β\mathrm{X}_{2}=\beta

X3=βX_{3}=\beta

X4=αX_{4}=\alpha

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2019
Paper
Paper 1
Subject
Chemistry
Chapter
Structure of Atom
Topic
Subatomic Particles
In the decay sequence, 92 238 U xrightarrow -x 1 90 234 Th… | JEE Advanced 2019 PYQ with Solution · DhiX AI