Physics · Nuclear Physics

JEE Advanced 2023 — Paper 2 — Question 25

In a radioactive decay process, the activity is defined as A=−dNdtA=-\frac{d N}{d t}, where N(t)N(t) is the number of radioactive nuclei at time tt. Two radioactive sources, S1S_{1} and S2S_{2} have same activity at time t=0t=0. At a later time, the activities of S1S_{1} and S2S_{2} are A1A_{1} and A2A_{2}, respectively. When S1S_{1} and S2S_{2} have just completed their 3rd 3^{\text {rd }} and 7th 7^{\text {th }} half-lives, respectively, the ratio A1/A2A_{1} / A_{2} is \qquad

Answer: 16

Numerical answer — enter this value.

Step-by-step solution

After 3rd 3^{\text {rd }} half lives, A1=A0(1/2)3\mathrm{A}_{1}=\mathrm{A}_{0}(1 / 2)^{3} After 7th 7^{\text {th }} half lives, A2=A0(1/2)7\mathrm{A}_{2}=\mathrm{A}_{0}(1 / 2)^{7} Where A0=\mathrm{A}_{0}= initial activity. (A1 A2)=16\left(\frac{\mathrm{A}_{1}}{\mathrm{~A}_{2}}\right)=16

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2023
Paper
Paper 2
Subject
Physics
Chapter
Nuclear Physics
Topic
Laws of Radioactive Decay
In a radioactive decay process, the activity is defined as A=-d N/d t… | JEE Advanced 2023 PYQ with Solution · DhiX AI