Chemistry · Chemical Bonding

JEE Advanced 2019 — Paper 1 — Question 22

Fusion of MnO2\mathrm{MnO}_{2} with KOH in presence of O2\mathrm{O}_{2} produces a salt W . Alkaline solution of W upon electrolytic oxidation yields another salt X . The manganese containing ions present in W and X , respectively, are Y and Z. Correct statement(s) is(are)

  1. Option A:

    In aqueous acidic solution, Y undergoes disproportionation reaction to give Z and MnO2\mathrm{MnO}_{2}

    Correct
  2. Option B:

    In both Y and Z,π\mathrm{Z}, \pi-bonding occurs between p-orbitals of oxygen and d-orbitals of manganese

    Correct
  3. Option C:

    Y is diamagnetic in nature while Z is paramagnetic

  4. Option D:

    Both Y and Z are coloured and have tetrahedral shape

    Correct

Answer: A, B, D

Step-by-step solution

y=Mn+6 and z=Mn+7\mathrm{y}=\mathrm{Mn}^{+6} \text { and } \mathrm{z}=\mathrm{Mn}^{+7}
Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2019
Paper
Paper 1
Subject
Chemistry
Chapter
Chemical Bonding
Topic
Hybridization and VSEPR
Fusion of MnO 2 with KOH in presence of O 2 produces a salt W .… | JEE Advanced 2019 PYQ with Solution · DhiX AI