Chemistry · Thermodynamics & Thermochemistry

JEE Advanced 2025 — Paper 1 — Question 40

Considering ideal gas behavior, the expansion work done (in kJ ) when 144 g of

water is electrolyzed completely under constant pressure at 300 K is \qquad .

Use: Universal gas constant (R)=8.3 J K−1 mol−1(\mathrm{R})=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}; Atomic mass (in amu): H=1,O=16\mathrm{H}=1, \mathrm{O}=16

Answer: 29.88

Numerical answer — enter this value.

Step-by-step solution

H2O(l)→H2( g)+12O2( g)\quad \mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{H}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g})

144 g - - 8 mol8 mol4 mol8 \mathrm{~mol} \quad 8 \mathrm{~mol} \quad 4 \mathrm{~mol}

W=−PΔV=−(Δn)RT\mathrm{W}=-\mathrm{P} \Delta \mathrm{V}=-(\Delta \mathrm{n}) \mathrm{RT}

Change in gaseous moles =12=12

⇒W=−12×8.3×3001000 kJ=−29.88 kJ\Rightarrow \quad \mathrm{W}=-\frac{12 \times 8.3 \times 300}{1000} \mathrm{~kJ}=-29.88 \mathrm{~kJ}.

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2025
Paper
Paper 1
Subject
Chemistry
Chapter
Thermodynamics & Thermochemistry
Topic
Work Done in Different Cases
Considering ideal gas behavior, the expansion work done (in kJ ) when… | JEE Advanced 2025 PYQ with Solution · DhiX AI