At 298 K, the limiting molar conductivity of a weak monobasic acid is 4 × 10 2 \; S cm 2 mol -1 . At 298 K, for an aqueous solution of the acid the degree of dissociation is α and the molar conductivity is y × 10 2 \; S cm 2 mol -1 . At 298 K, upon 20 times dilution with water, the molar conductivity of the solution becomes 3y × 10 2 \; S cm 2 mol -1 . The value of y is .

Chemistry · Electrochemistry

JEE Advanced 2021 — Paper 2 — Question 35

At 298 K, the limiting molar conductivity of a weak monobasic acid is

4 \times 10^{2} \; \text{S cm}^{2} \text{mol}^{-1}.

At 298 K, for an aqueous solution of the acid the degree of dissociation is $\alpha$ and the molar conductivity is

y \times 10^{2} \; \text{S cm}^{2} \text{mol}^{-1}.

At 298 K, upon 20 times dilution with water, the molar conductivity of the solution becomes

3y \times 10^{2} \; \text{S cm}^{2} \text{mol}^{-1}.

The value of $\mathbf{y}$ is $\qquad$ .

Numerical answer — enter this value.

$\alpha=\frac{y}{4} ; \quad y=4 \alpha=4 \times 0.22=0.88$

Answer key and solution verified before publishing.

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.