Physics · Moving Charges and Magnetic Field

JEE Advanced 2021 — Paper 1 — Question 9

An α\alpha-particle (mass 4 amu ) and a singly charged sulfur ion (mass 32 amu ) are initially at rest. They are accelerated through a potential V and then

allowed to pass into a region of uniform magnetic field which is normal to the velocities of the particles. Within this region,

the α\alpha-particle and the sulfur ion move in circular orbits of radii rαr_{\alpha} and rsr_{s}, respectively.

The ratio (rs/rα)\left(r_{s} / r_{\alpha}\right) is \qquad .

Answer: 4

Numerical answer — enter this value.

Step-by-step solution

ra=2 muqu Vqa B\mathrm{r}_{a}=\frac{\sqrt{2 \mathrm{~m}_{u} \mathrm{q}_{u} \mathrm{~V}}}{\mathrm{q}_{a} \mathrm{~B}}

rs=2 msqsVqsB\mathrm{r}_{\mathrm{s}}=\frac{\sqrt{2 \mathrm{~m}_{\mathrm{s}} \mathrm{q}_{\mathrm{s}} V}}{\mathrm{q}_{\mathrm{s}} \mathrm{B}} rsrα=mSqSqαmα=(321)(24)\frac{\mathrm{r}_{\mathrm{s}}}{\mathrm{r}_{\alpha}}=\sqrt{\frac{\mathrm{m}_{\mathrm{S}}}{\mathrm{q}_{\mathrm{S}}} \frac{\mathrm{q}_{\alpha}}{\mathrm{m}_{\alpha}}}=\sqrt{\left(\frac{32}{1}\right)\left(\frac{2}{4}\right)}

rsrα=4\frac{\mathrm{r}_{\mathrm{s}}}{\mathrm{r}_{\alpha}}=4

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2021
Paper
Paper 1
Subject
Physics
Chapter
Moving Charges and Magnetic Field
Topic
Motion of Charged Particles in magnetic Fields