Among V ( CO ) 6 , Cr ( CO ) 5 , Mn ( CO ) 5 , Fe ( CO ) 5 , [ Co ( CO ) 3 ] 3- , [ Cr ( CO ) 4 ] 4- and Ir ( CO ) 3 , the total number of species isoelectronic with Ni ( CO ) 4 is \ \ \ \ \ [Given, atomic number: V =23, Cr =24, Mn =2 overline 5, Fe =26, Co =27 , Ni =28, Cu =29 , Ir =77 ]

Chemistry · d and f Block Elements

JEE Advanced 2024 — Paper 1 — Question 41

Among $\mathrm{V}(\mathrm{CO})_{6}, \mathrm{Cr}(\mathrm{CO})_{5}, \mathrm{Mn}(\mathrm{CO})_{5}, \mathrm{Fe}(\mathrm{CO})_{5},\left[\mathrm{Co}(\mathrm{CO})_{3}\right]^{3-},\left[\mathrm{Cr}(\mathrm{CO})_{4}\right]^{4-}$ and $\operatorname{Ir}(\mathrm{CO})_{3}$ , the total number of species isoelectronic with $\mathrm{Ni}(\mathrm{CO})_{4}$ is $\_\_\_\_\_$ [Given, atomic number: $\mathrm{V}=23, \mathrm{Cr}=24, \mathrm{Mn}=2 \overline{5, \mathrm{Fe}=26, \mathrm{Co}=27}, \mathrm{Ni}=28, \mathrm{Cu}=29$ , $\mathrm{Ir}=77$ ]

Answer: 1

Numerical answer — enter this value.

Step-by-step solution

$\mathrm{Ni}(\mathrm{CO})_{4}=84$ $\mathrm{V}(\mathrm{CO})_{6}=107$

\begin{aligned} & \mathrm{Cr}(\mathrm{CO})_{5}=94 \\& \mathrm{Mn}(\mathrm{CO})_{5}=95 \\& \mathrm{Fe}(\mathrm{CO})_{5}=96 \\& {\left[\mathrm{Co}(\mathrm{CO})_{3}\right]^{-3}=72} \\& {\left[\mathrm{Cr}(\mathrm{CO})_{4}\right]^{-4}=84\left[\text { Isoelectronic with } \mathrm{Ni}(\mathrm{CO})_{4}\right]} \\& {\left[\operatorname{lr}(\mathrm{CO})_{3}\right]=119} \end{aligned}

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Exam: JEE Advanced 2024
Paper: Paper 1
Subject: Chemistry
Chapter: d and f Block Elements
Topic: Properties of general compounds of transition elements