Physics · Gravitation

JEE Advanced 2018 — Paper 2 — Question 15

A planet of mass MM, has two natural satellites with masses m1m_{1} and m2m_{2}. The radii of their circular orbits are R1R_{1} and R2R_{2} respectively. Ignore the gravitational force between the satellites. Define v1,L1,K1v_{1}, L_{1}, K_{1} and T1T_{1} to be, respectively, the orbital speed, angular momentum, kinetic energy and time period of revolution of satellite 1 ; and v2,L2,K2v_{2}, L_{2}, K_{2} and T2T_{2} to be the corresponding quantities of satellite 2 . Given m1/m2=2m_{1} / m_{2}=2 and R1/R2=1/4R_{1} / R_{2}=1 / 4, match the ratios in List-I to the numbers in List-II.

List-IList-II
P. v1v2\frac{\mathrm{v}_{1}}{\mathrm{v}_{2}}1. 18\frac{1}{8}
Q. L1 L2\frac{\mathrm{L}_{1}}{\mathrm{~L}_{2}}2. 11
R. K1 K2\frac{\mathrm{K}_{1}}{\mathrm{~K}_{2}}3. 22
S. T1 T2\frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}4. 88
  1. Option A:

    P→4;Q→2;R→1; S →3\mathrm{P} \rightarrow 4 ; \mathrm{Q} \rightarrow 2 ; \mathrm{R} \rightarrow \mathbf{1 ; ~ S ~} \rightarrow 3

  2. Option B:

    P→3;Q→2;R→4;S→1\mathrm{P} \rightarrow 3 ; \mathrm{Q} \rightarrow 2 ; \mathrm{R} \rightarrow 4 ; \mathrm{S} \rightarrow 1

    Correct
  3. Option C:

    P→2;Q→3;R→1;S→4\mathrm{P} \rightarrow 2 ; \mathrm{Q} \rightarrow 3 ; \mathrm{R} \rightarrow 1 ; \mathrm{S} \rightarrow 4

  4. Option D:

    P→2;Q→3;R→4;S→1\mathbf{P} \rightarrow 2 ; \mathrm{Q} \rightarrow \mathbf{3} ; \mathrm{R} \rightarrow 4 ; \mathrm{S} \rightarrow \mathbf{1}

Answer: B

Step-by-step solution

v∝1r\mathrm{v} \propto \frac{1}{\sqrt{\mathrm{r}}}, Hence correct answer is 'B'

Also, T∝r3/2T \propto r^{3 / 2}

K∝mr\mathrm{K} \propto \frac{\mathrm{m}}{\mathrm{r}}

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2018
Paper
Paper 2
Subject
Physics
Chapter
Gravitation
Topic
Motion of Satellites and Escape Speed
A planet of mass M , has two natural satellites with masses m 1 and m… | JEE Advanced 2018 PYQ with Solution · DhiX AI