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Chemistry · Biomolecules

JEE Main 2026 — 8 April, Evening Shift — Question 56

Which statements are True? A. In Hoffmann bromamide degradation, 4 moles of NaOH and 2 moles of Br2\mathrm{Br}_{2} are consumed per mole of an amide B. Hoffmann bromamide reaction is not given by alkyl amides. C. Primary amines can be synthesized by Hoffmann bromamide degradation. D. Secondary amide on reaction with Br2\mathrm{Br}_{2} and NaOH will give secondary amine. E. The by-products of Hoffmann degradation are Na2CO3,NaBr\mathrm{Na}_{2} \mathrm{CO}_{3}, \mathrm{NaBr} and H2O\mathrm{H}_{2} \mathrm{O}. Choose the correct answer from the options given below :

  1. Option A:

    A, C and E only

  2. Option B:

    B, C and D only

  3. Option C:

    C and E only

    Correct
  4. Option D:

    C, D and E only

Answer: C

Step-by-step solution

Hoffmann bromamide degradation reaction -

R−NH2+Na2CO3+2NaBr+2H2O1∘ Amine \begin{aligned} & \mathrm{R}-\mathrm{NH}_{2}+\mathrm{Na}_{2} \mathrm{CO}_{3}+2 \mathrm{NaBr}+2 \mathrm{H}_{2} \mathrm{O} & 1^{\circ} \text { Amine } \end{aligned}

Statement (A) - False Statement (B) - False Statement (C) - True Statement (D) - False Statement (E) - True

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
8 April, Evening Shift
Subject
Chemistry
Chapter
Biomolecules
Topic
Introduction to Biomolecules & Carbohydrates

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