Chemistry · Chemical Bonding

JEE Main 2025 — 2 April, Evening Shift — Question 2

Which among the following molecules is (a) involved in $s p^{3} d$ hybridization, (b) has different bond lengths and (c) has lone pair of electrons on the central atom?

Option A:
$\mathrm{XeF}_{4}$
Option B:
$\mathrm{XeF}_{2}$
Option C:
$\mathrm{PF}_{5}$
Option D:
$\mathrm{SF}_{4}$
Correct

Answer: D

Step-by-step solution

$(S-F)_{a}>(S-F)_{e}$

$\mathrm{SF}_{4}$ has 4 bond pairs of electrons and 1 lone pair of electrons.

Since, steric number is 5 ,

Hybridisation of $\mathrm{SF}_{4}=\mathrm{sp}^{3} \mathrm{~d}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 2 April, Evening Shift
Subject: Chemistry
Chapter: Chemical Bonding
Topic: Hybridization and VSEPR

In 3,3-dimethylhex-1-en-4-yne, there are \ \ \ \ \ s p^3 , \ \ \ \ \ s p^2 and \ \ \ \ \ s p hybridised carbon atoms respectively.

Answer: D

Step-by-step solution

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