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Physics · Units, Dimensions & Error Analysis

JEE Main 2026 — 28 January, Morning Shift — Question 37

When both jaws of vernier callipers touch each other, zero mark of the vernier scale is right to zero mark of main scale, 4th 4^{\text {th }} mark on vernier scale coincides with certain mark on the main scale. While measuring the length of a cylinder, observer observes 15 divisions on main scale and 5th 5^{\text {th }} division of vernier scale coincides with a min scale division. Measured length of cylinder is ____\_\_\_\_ mm . (Least count of Vernier calliper =0.1 mm=0.1 \mathrm{~mm} )

  1. Option A:

    15.4

  2. Option B:

    15.1

    Correct
  3. Option C:

    15.5

  4. Option D:

    15.9

Answer: B

Step-by-step solution

Reading =MSR+(VSR×LC)−=\mathrm{MSR}+(\mathrm{VSR} \times \mathrm{LC})- (zero Error) =15 mm+(5×0.1 mm)−(4×0.1 mm)=15 \mathrm{~mm}+(5 \times 0.1 \mathrm{~mm})-(4 \times 0.1 \mathrm{~mm}) Reading = 15.1 mm ∴ℓ=15.1 mm\therefore \ell=15.1 \mathrm{~mm}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
28 January, Morning Shift
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Vernier Calipers and Screw Gauge
When both jaws of vernier callipers touch each other, zero mark of… | JEE Main 2026 PYQ with Solution · DhiX AI