When Δ H vap =30 kJ / mol and Δ S vap =75 J mol -1 K -1 , then the temperature of vapour, at one atmosphere is K.

Chemistry · Thermodynamics & Thermochemistry

JEE Main 2024 — 9 April, Shift 2 — Question 82

When $\Delta \mathrm{H}_{\text {vap }}=30 \mathrm{~kJ} / \mathrm{mol}$ and $\Delta \mathrm{S}_{\text {vap }}=75 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$ , then the temperature of vapour, at one

atmosphere is $\qquad$ K.

Answer: 400

Numerical answer — enter this value.

Step-by-step solution

At equilibrium $\Delta \mathrm{G}_{\mathrm{PT}}=0$

$\Delta \mathrm{H}_{\text {vap }}=\mathrm{T} \Delta \mathrm{S}_{\text {vap }}$

$30 \times 1000=\mathrm{T} \times 75$

$\mathrm{T}=400 \mathrm{~K}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 9 April, Shift 2
Subject: Chemistry
Chapter: Thermodynamics & Thermochemistry
Topic: Entropy Change in Different Processes