We have three aqueous solutions of NaCl labelled as 'A', 'B' and 'C' with concentration 0.1 M , 0.01 M \& 0.001 M , respectively. The value of van t' Haft factor (i) for these solutions will be in the order.

Chemistry · Solutions and Colligative Properties

JEE Main 2024 — 1 February, Shift 1 — Question 70

We have three aqueous solutions of NaCl labelled as 'A', 'B' and 'C' with concentration 0.1 M , $0.01 \mathrm{M} \& 0.001 \mathrm{M}$ , respectively. The value of van t' Haft factor (i) for these solutions will be in the order.

Option A:
${{i}_{A}}<{{i}_{B}}<{{i}_{C}}$
Option B:
${{i}_{A}}<{{i}_{C}}<{{i}_{B}}$
Option C:
${{i}_{A}}={{i}_{\mathbf{B}}}={{i}_{C}}$
Option D:
${{i}_{A}}>{{i}_{\mathbf{B}}}>{{i}_{C}}$
Correct

Answer: D

Step-by-step solution

${{C}_{A}}$ =0.1 M

${{C}_{B}}$ =0.01 M

${{C}_{C}}$ =0.001 M

As Concentration increses i will decreses

so ; ${{i}_{A}}<{{i}_{B}}<{{i}_{C}}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 1 February, Shift 1
Subject: Chemistry
Chapter: Solutions and Colligative Properties
Topic: Abnormal Colligative Properties - van't Hoff Factor