Physics · Atomic Physics

JEE Main 2026 — 2 April, Evening Shift — Question 19

Using Bohr's model, calculate the ratio of the magnetic fields generated due to the motion of the electrons in the $2^{\mathrm{nd}}$ and $4^{\mathrm{th}}$ orbits of hydrogen atom

Answer: 64

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Step-by-step solution

$B \propto \frac{Z^3}{n^5}$ → $\frac{B_2}{B_4} = \frac{4^5}{2^5} = 64$

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Exam: JEE Main 2026
Paper: 2 April, Evening Shift
Subject: Physics
Chapter: Atomic Physics
Topic: Rutherford's and Bohr's Model of Atom

The surface of sodium metal is irradiated with radiation of wavelength x nm . The kinetic energy of ejected electrons is 2.8 × 10^-20 J .…

Answer: 64

Step-by-step solution

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