Physics · Capacitors and R-C Circuits

JEE Main 2026 — 5 April, Evening Shift — Question 12

Under steady state condition the potential difference across the capacitor in the circuit is V.

Question figure
  1. Option A:

    0.5

    Correct
  2. Option B:

    1.5

  3. Option C:

    0

  4. Option D:

    2

Answer: A

Step-by-step solution

Current i=2/(6+2)=1/4i = 2/(6+2) = 1/4 A. Voltage across 2Ω resistor = i×2=0.5i\times2 = 0.5 V. In steady state, capacitor voltage equals voltage across parallel resistor = 0.5 V.

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Physics
Chapter
Capacitors and R-C Circuits
Topic
Combination of Capacitors and Circuit Analysis
Under steady state condition the potential difference across the… | JEE Main 2026 PYQ with Solution · DhiX AI