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Physics · Mechanical Properties of Matter

JEE Main 2025 — 7 April, Morning Shift — Question 49

Two wires AA and BB are made of same material having ratio of lengths LALB=13\frac{L_{A}}{L_{B}}=\frac{1}{3} and their diameters ratio dAdB=2\frac{d_{A}}{d_{B}}=2. If both the wires are stretched using same force, what would be the ratio of their respective elongations?

  1. Option A:

    1:31: 3

  2. Option B:

    1:61: 6

  3. Option C:

    1:121: 12

    Correct
  4. Option D:

    3:43: 4

Answer: C

Step-by-step solution

Strain =ΔLL= Stress y=FAy=\frac{\Delta L}{L}=\frac{\text { Stress }}{y}=\frac{F}{A y}

So, ΔL(A)ΔL(B)=LAA(B)A(A)LB=13×14=112\frac{\Delta L(A)}{\Delta L(B)}=\frac{L_{A} A_{(B)}}{A_{(A)} L_{B}}=\frac{1}{3} \times \frac{1}{4}=\frac{1}{12}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
7 April, Morning Shift
Subject
Physics
Chapter
Mechanical Properties of Matter
Topic
Longitudinal Strain and Elastic Potential Energy