JEE Main 2025 — 4 April, Morning Shift — Question 67

Two slabs with square cross section of different materials $(1,2)$ with equal sides $(I)$ and thickness $d_{1}$

and $d_{2}$ such that $d_{2}=2 d_{1}$ and $l>d_{2}$. Considering lower edges of these slabs are fixed

to the floor, we apply equal shearing force on the narrow faces. The angle of deformation is

$\theta_{2}=2 \theta_{1}$. If the shear moduli of material 1 is $4 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}$, then shear moduli of material 2 is $x \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}$,

where value of $x$ is $\qquad$