Physics · Electrostatics

JEE Main 2026 — 23 January, Morning Shift — Question 38

Two point charges 2 q and q are placed at vertex A and centre of face CDEF of the cube as shown in figure. The electric flux passing through the cube is :

Option A:
$\frac{3 q}{\varepsilon_{0}}$
Option B:
$\frac{q}{\varepsilon_{0}}$
Option C:
$\frac{3 q}{2 \varepsilon_{0}}$
Option D:
$\frac{3 q}{4 \varepsilon_{0}}$
Correct

Answer: D

Step-by-step solution

$\phi=\frac{\mathrm{Q}_{\text {in }}}{\varepsilon_{0}}$ $\phi=\frac{\frac{q}{4}+\frac{q}{2}}{\varepsilon_{0}}=\frac{3 q}{4 \varepsilon_{0}}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 23 January, Morning Shift
Subject: Physics
Chapter: Electrostatics
Topic: Properties of Electric Charge and Coulomb's Law