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Physics · Nuclear Physics

JEE Main 2026 — 4 April, Morning Shift — Question 4

Two nuclei of mass number 3 combine with another nucleus of mass number 4 to yield a nucleus of mass number 10. If the binding energy per nucleon for mass numbers 3, 4 and 10 are 5.6 MeV, 7.4 MeV and 6.1 MeV respectively, then in the process, ΔMc2=\Delta Mc^2 = ______ MeV.

  1. Option A:

    6.9

  2. Option B:

    7.9

  3. Option C:

    2.2

    Correct
  4. Option D:

    4.3

Answer: C

Step-by-step solution

ΔMc² = [2×3×5.6 + 4×7.4 - 10×6.1] = 33.6 + 29.6 - 61 = 2.2 MeV

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
4 April, Morning Shift
Subject
Physics
Chapter
Nuclear Physics
Topic
Mass Defect, Binding Energy and Q-Value of Nuclear Reaction
Two nuclei of mass number 3 combine with another nucleus of mass… | JEE Main 2026 PYQ with Solution · DhiX AI