Physics · Kinetic Theory of Gases

JEE Main 2024 — 1 February, Shift 1 — Question 34

Two moles a monoatomic gas is mixed with six moles of a diatomic gas. The molar specific heat of the mixture at constant volume is :

  1. Option A:

    94R\frac{9}{4} R

    Correct
  2. Option B:

    74R\frac{7}{4} R

  3. Option C:

    32R\frac{3}{2} R

  4. Option D:

    52R\frac{5}{2} R

Answer: A

Step-by-step solution

Cv=n1Cv11+n2Cv2n1+n2{{C}_{v}}=\frac{{{n}_{1}}{{C}_{{{v}_{1}}}}1+{{n}_{2}}{{C}_{{{v}_{2}}}}}{{{n}_{1}}+{{n}_{2}}}

\begin{array}{*{35}{r}}{} & ~=\frac{2\times \frac{3}{2}\text{R}+6\times \frac{5}{2}\text{R}}{2+6} \\{} & ~=\frac{9}{4}\text{R} \\\end{array}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Physics
Chapter
Kinetic Theory of Gases
Topic
Equipartition Law of Energy and Degrees of Freedom
Two moles a monoatomic gas is mixed with six moles of a diatomic gas.… | JEE Main 2024 PYQ with Solution · DhiX AI