Mathematics · Probability

JEE Main 2024 — 30 January, Shift 1 — Question 11

Two integers $x$ and $y$ are chosen with replacement from the set $\{0,1,2,3, \ldots . .10\}$ . Then the probability that $|x-y|>5$ is :

Answer: A

If $x=0, y=6,7,8,9,10$

If $x=1, y=7,8,9,10$

If $x=2, y=8,9,10$

If $x=3, y=9,10$

If $x=4, y=10$

If $x=5, y=$

no possible value Total possible ways

$=(5+4+3+2+1) \times 2$ $=30$

Required probability

$=\frac{30}{11 \times 11}=\frac{30}{121}$

Answer key and solution verified before publishing.

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