Physics · Geometrical Optics

JEE Main 2024 — 27 January, Shift 1 — Question 51

Two immiscible liquids of refractive indices $\frac{8}{5}$ and $\frac{3}{2}$ respectively are put in a beaker as shown in the figure. The height of each column is 6 cm . A coin is placed at the bottom of the beaker. For near normal vision, the apparent depth of the coin is $\frac{\alpha}{4} \mathrm{~cm}$ . The value of $\alpha$ is $\_\_\_\_\_\_\_$

Answer: 31

Numerical answer — enter this value.

Step-by-step solution

$\mathrm{h}_{\text {app }}=\frac{\mathrm{h}_{1}}{\mu_{1}}+\frac{\mathrm{h}_{2}}{\mu_{2}}=\frac{6}{3 / 2}+\frac{6}{8 / 5}=4+\frac{15}{4}=\frac{31}{4} \mathrm{~cm}$

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Exam: JEE Main 2024
Paper: 27 January, Shift 1
Subject: Physics
Chapter: Geometrical Optics
Topic: Apparent Depth, Glass Slab, Prism and Dispersion

If the refractive index of the material of a prism is cot (frac A2 ) , where A is the angle of prism then the angle of minimum deviation…

Answer: 31

Step-by-step solution

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