Physics · Motion in Plane

JEE Main 2026 — 8 April, Evening Shift — Question 6

Two identical bodies, projected with the same speed at two different angles cover the same horizontal range R. If the time of flight of these bodies are 5 s and 10 s, respectively, then the value of R is $\mathrm{m}$ . (Take $\mathrm{g} = 10\mathrm{m/s}^2$ )

Option A:
250
Correct
Option B:
25
Option C:
500
Option D:
125

Answer: A

Step-by-step solution

For complementary angles, $T_1 = \frac{2u\sin\theta}{g}=10$ , $T_2 = \frac{2u\cos\theta}{g}=5$ . Multiply: $\frac{4u^2\sin\theta\cos\theta}{g^2}=50$ ⇒ $R = \frac{u^2\sin2\theta}{g} = \frac{2u^2\sin\theta\cos\theta}{g} = 25g = 250$ m.

Answer key and solution verified before publishing.

Practise Motion in Plane

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free

Exam: JEE Main 2026
Paper: 8 April, Evening Shift
Subject: Physics
Chapter: Motion in Plane
Topic: Oblique and Horizontal Projectile Motion