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Physics · Rotational Dynamics

JEE Main 2026 — 21 January, Evening Shift — Question 30

Two cars A and B each of mass 103 kg10^{3} \mathrm{~kg} are moving on parallel tracks separated by a distance of 10 m , in same direction with speeds 72 km/h72 \mathrm{~km} / \mathrm{h} and 36 km/h36 \mathrm{~km} / \mathrm{h}. The magnitude of angular momentum of car A with respect to car B is ____\_\_\_\_ J.s.

  1. Option A:

    3.6×1053.6 \times 10^{5}

  2. Option B:

    10510^{5}

    Correct
  3. Option C:

    3×1053 \times 10^{5}

  4. Option D:

    2×1052 \times 10^{5}

Answer: B

Step-by-step solution

L=m.Vrel r⊥\mathrm{L}=\mathrm{m} . \mathrm{V}_{\text {rel }} \mathrm{r}_{\perp}

=1000×(36×518)×10=105 kg m2/s\begin{aligned} & =1000 \times\left(36 \times \frac{5}{18}\right) \times 10 & =10^{5} \mathrm{~kg} \mathrm{~m}^{2} / \mathrm{s} \end{aligned}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
21 January, Evening Shift
Subject
Physics
Chapter
Rotational Dynamics
Topic
Angular Momentum and its Conservation

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