Start free

Physics · Semiconductor and Electronic Devices

JEE Main 2026 — 4 April, Morning Shift — Question 12

Two 4‑bit binary numbers A = 1101 and B = 1010 are given as inputs to the logic circuit shown. The output Y is

Question figure
  1. Option A:

    1101

    Correct
  2. Option B:

    10

  3. Option C:

    111

  4. Option D:

    1000

Answer: A

Step-by-step solution

Y = A⋅B‾\overline{A \cdot B} = A + B‾\overline{B}. A=1101, B‾\overline{B}=0101, sum=1101

Answer key and solution verified before publishing.

Practise Semiconductor and Electronic Devices

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free
Exam
JEE Main 2026
Paper
4 April, Morning Shift
Subject
Physics
Chapter
Semiconductor and Electronic Devices
Topic
Boolean Algebra, Truth Tables and Logic Gates
Two 4‑bit binary numbers A = 1101 and B = 1010 are given as inputs to… | JEE Main 2026 PYQ with Solution · DhiX AI