Start free

Physics · Current Electricity

JEE Main 2024 — 9 April, Shift 2 — Question 51

To determine the resistance (R) of a wire, a circuit is designed below, The V-I characteristic curve for this circuit is plotted for the voltmeter and the ammeter readings as shown in figure. The value of R is .... \qquad Ω\Omega.

figure

Question figure

Answer: 2500

Numerical answer — enter this value.

Step-by-step solution

Req⁡=104R104+R\quad \operatorname{Req}=\frac{10^{4} \mathrm{R}}{10^{4}+\mathrm{R}}

E=4 V,I=2 mA\mathrm{E}=4 \mathrm{~V}, \mathrm{I}=2 \mathrm{~mA}

I=EReq⁡⇒2×10−3=4(104+R)104R\mathrm{I}=\frac{\mathrm{E}}{\operatorname{Req}} \Rightarrow 2 \times 10^{-3}=\frac{4\left(10^{4}+R\right)}{10^{4} \mathrm{R}}

⇒20R=40000+4R\Rightarrow 20 \mathrm{R}=40000+4 \mathrm{R} 16R=4000016 \mathrm{R}=40000

R=2500Ω\mathrm{R}=2500 \Omega

Answer key and solution verified before publishing.

Practise Current Electricity

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free
Exam
JEE Main 2024
Paper
9 April, Shift 2
Subject
Physics
Chapter
Current Electricity
Topic
Circuit Analysis, Kirchhoff's Law and Nodal Analysis

More Current Electricity questions from this paper

To determine the resistance (R) of a wire, a circuit is designed… | JEE Main 2024 PYQ with Solution · DhiX AI