Chemistry · Chemical Kinetics

JEE Main 2024 — 6 April, Shift 1 — Question 78

Time required for 99.9%99.9 \% completion of a first order reaction is \qquad time the time required for completion of 90%90 \% reaction.(nearest integer).

Answer: 3

Numerical answer — enter this value.

Step-by-step solution

K=1t99.9%ln⁡(1000.1)=1t90%ln⁡(10010)\mathrm{K}=\frac{1}{\mathrm{t}_{99.9 \%}} \ln \left(\frac{100}{0.1}\right)=\frac{1}{\mathrm{t}_{90 \%}} \ln \left(\frac{100}{10}\right)

t99.9%=t90%ℓn⁡(103)ℓn10\mathrm{t}_{99.9 \%}=\mathrm{t}_{90 \%} \frac{\operatorname{\ell n}\left(10^{3}\right)}{\ell \mathrm{n} 10} t99.9%=t90%×3\mathrm{t}_{99.9 \%}=\mathrm{t}_{90 \%} \times 3

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Chemistry
Chapter
Chemical Kinetics
Topic
Integrated Rate Laws
Time required for 99.9 \% completion of a first order reaction is… | JEE Main 2024 PYQ with Solution · DhiX AI