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Physics · Thermodynamics

JEE Main 2025 — 4 April, Evening Shift — Question 60

There are two vessels filled with an ideal gas where volume of one is double the volume of other. The large vessel contains the gas at 8 kPa at 1000 K while the smaller vessel contains the gas at 7 kPa at 500 K . If the vessels are connected to each other by a thin tube allowing the gas to flow and the temperature of both vessels is maintained at 600 K , at steady state the pressure in the vessels will be (in kPa ).

  1. Option A:

    18

  2. Option B:

    6

    Correct
  3. Option C:

    24

  4. Option D:

    4.4

Answer: B

Step-by-step solution

PVT=P1V1T1+P2V2T2\frac{P V}{T}=\frac{P_{1} V_{1}}{T 1}+\frac{P_{2} V_{2}}{T_{2}}

P.3V600=8×2V1000+7×V500\frac{P .3 V}{600}=\frac{8 \times 2 V}{1000}+\frac{7 \times V}{500}

P=6kPa\mathrm{P}=6 \mathrm{kPa}

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
4 April, Evening Shift
Subject
Physics
Chapter
Thermodynamics
Topic
Efficiency of Processes and Miscellaneous Problems

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