Physics · Current Electricity

JEE Main 2025 — 4 April, Evening Shift — Question 56

There are $n$ number of identical electric bulbs, each is designed to draw a power $p$ independently from the mains supply. They are now joined in series across the mains supply. The total power drawn by the combination is

Option A:
$p$
Option B:
$n p$
Option C:
$\frac{p}{n}$
Correct
Option D:
$\frac{p}{n}$

Answer: C

Step-by-step solution

$\frac{v^{2}}{R}=p$

$R_{\text {eq }}=n R$

$p^{\prime}=\frac{v^{2}}{R_{\text {eq }}}=\frac{v^{2}}{n R} \Rightarrow \frac{p}{n}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 4 April, Evening Shift
Subject: Physics
Chapter: Current Electricity
Topic: Heating Effects of Current and Thermal Powe