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Physics · Motion in one Dimension

JEE Main 2026 — 5 April, Evening Shift — Question 4

The velocity(v) versus time (t) plot of a particle is shown in the figure, for a time interval of 40s. The total distance travelled by the particle and the average velocity during this period are, respectively

Question figure
  1. Option A:

    25m and zero

  2. Option B:

    50m and zero

  3. Option C:

    100m and zero

    Correct
  4. Option D:

    100m and 2.5m/s2.5\mathrm{m/s}

Answer: C

Step-by-step solution

Distance = area under v-t graph: two triangles each area = 12×20×5=50\frac12 \times20\times5=50, total 100 m. Displacement = 0 (positive and negative areas cancel), so average velocity = 0.

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
5 April, Evening Shift
Subject
Physics
Chapter
Motion in one Dimension
Topic
Graphical Interpretation of 1-D motion
The velocity(v) versus time (t) plot of a particle is shown in the… | JEE Main 2026 PYQ with Solution · DhiX AI