Physics · Semiconductor and Electronic Devices

JEE Main 2024 — 4 April, Shift 1 — Question 46

The value of net resistance of the network as shown in the given figure is :

Answer: C

Diode 2 is in reverse bias So current will not flow in branch of $2^{\text {nd }}$ diode, So we can assume it to be broken wire.

Diode 1 is in forward bias So it will behave like conducting wire.

So new circuit will be $\mathrm{R}_{\mathrm{eq}}=\frac{15 \times 10}{15+10}=\frac{15 \times 10}{25}=6 \Omega$

${{\text{R}}_{\text{eq}}}=\frac{15\times 10}{15+10}=\frac{15\times 10}{25}=6\text{ }\!\!\Omega\!\!\text{ }$

Answer key and solution verified before publishing.

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