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Chemistry · Periodicity of Elements and Periodic Properties

JEE Main 2025 — 29 January, Evening Shift — Question 10

The type of oxide formed by the element among Li,  Na,  Be,  Mg,  B\mathrm{Li},\;\mathrm{Na}, \;\mathrm{Be}, \;\mathrm{Mg}, \;\mathrm{B} and Al\mathrm{Al} that has the least atomic radius is :

  1. Option A:

    A2O3\mathrm{A}_{2} \mathrm{O}_{3}

    Correct
  2. Option B:

    AO2\mathrm{AO}_{2}

  3. Option C:

    AO\mathrm{AO}

  4. Option D:

    A2O\mathrm{A}_{2} \mathrm{O}

Answer: A

Step-by-step solution

Atomic radius decreases across a period and increases down a group.

Among Li, Na, Be, Mg, B and Al, the smallest atom is B.

Boron forms oxide B2_2O3_3.

Thus the type of oxide is A2_2O3_3.

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
29 January, Evening Shift
Subject
Chemistry
Chapter
Periodicity of Elements and Periodic Properties
Topic
Periodicity in Physical Properties (shielding and sizes)

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