The type of hybridization and the magnetic property of [ MnCl 6 ] 3- are,

s p 3 d 2 , paramagnetic with four unpaired electrons.

sp 3 d 2 , paramagnetic with two unpaired electrons.

d 2 sp 3 , paramagnetic with two unpaired electrons.

d 2 s p 3 , paramagnetic with four unpaired electrons.

Chemistry · Coordination Compounds

JEE Main 2025 — 2 April, Evening Shift — Question 8

The type of hybridization and the magnetic property of $\left[\mathrm{MnCl}_{6}\right]^{3-}$ are,

Option A:
$\mathrm{sp}^{3} \mathrm{~d}^{2}$ , paramagnetic with two unpaired electrons.
Option B:
$\mathrm{d}^{2} \mathrm{sp}^{3}$ , paramagnetic with two unpaired electrons.
Option C:
$s p^{3} d^{2}$ , paramagnetic with four unpaired electrons.
Correct
Option D:
$d^{2} s p^{3}$ , paramagnetic with four unpaired electrons.

$\mathrm{Cl}^{-}$ with $\mathrm{Mn}^{3+}$ is a weak field ligand

$\mathrm{Mn}^{3+} \Rightarrow 3 \mathrm{~d}^{4} \Rightarrow \mathrm{t}^{3}{ }_{2 \mathrm{~g}} \mathrm{e}_{\mathrm{g}}{ }^{1}$

Hybridisation $=s p^{3} \mathrm{~d}^{2}$ with 4 unpaired electron and paramagnetic.

Answer key and solution verified before publishing.

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