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Chemistry · Chemical Bonding

JEE Main 2024 — 29 January, Shift 2 — Question 84

The total number of molecules with zero dipole moment among

CH4,BF3,H2O,HF,NH3,CO2\mathrm{CH}_{4}, \mathrm{BF}_{3}, \mathrm{H}_{2} \mathrm{O}, \mathrm{HF}, \mathrm{NH}_{3}, \mathrm{CO}_{2} and SO2\mathrm{SO}_{2} is ____\_\_\_\_ .

Answer: 3

Numerical answer — enter this value.

Step-by-step solution

Given molecules: CH4, BF3, H2O, HF, NH3, CO2, SO2\text{Given molecules: } \mathrm{CH_4},\ \mathrm{BF_3},\ \mathrm{H_2O},\ \mathrm{HF},\ \mathrm{NH_3},\ \mathrm{CO_2},\ \mathrm{SO_2} CH4: Tetrahedral and symmetrical ⇒Dipole moment=0\mathrm{CH_4}: \text{ Tetrahedral and symmetrical } \Rightarrow \text{Dipole moment} = 0 BF3: Trigonal planar and symmetrical ⇒Dipole moment=0\mathrm{BF_3}: \text{ Trigonal planar and symmetrical } \Rightarrow \text{Dipole moment} = 0 H2O: Bent shape, polar bonds do not cancel ⇒Dipole moment≠0\mathrm{H_2O}: \text{ Bent shape, polar bonds do not cancel } \Rightarrow \text{Dipole moment} \ne 0 HF: Diatomic polar molecule ⇒Dipole moment≠0\mathrm{HF}: \text{ Diatomic polar molecule } \Rightarrow \text{Dipole moment} \ne 0 NH3: Trigonal pyramidal, not symmetrical ⇒Dipole moment≠0\mathrm{NH_3}: \text{ Trigonal pyramidal, not symmetrical } \Rightarrow \text{Dipole moment} \ne 0 CO2: Linear and symmetrical ⇒Dipole moment=0\mathrm{CO_2}: \text{ Linear and symmetrical } \Rightarrow \text{Dipole moment} = 0 SO2: Bent shape ⇒Dipole moment≠0\mathrm{SO_2}: \text{ Bent shape } \Rightarrow \text{Dipole moment} \ne 0 Total molecules with zero dipole moment: CH4, BF3, CO2⇒3\text{Total molecules with zero dipole moment: } \mathrm{CH_4},\ \mathrm{BF_3},\ \mathrm{CO_2} \Rightarrow \boxed{3}

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Exam
JEE Main 2024
Paper
29 January, Shift 2
Subject
Chemistry
Chapter
Chemical Bonding
Topic
Dipole Moment and Fajans' Rule

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