Mathematics · Quadratic Equations

JEE Main 2026 — 21 January, Morning Shift — Question 19

The sum of all the roots of the equation (x−1)2−5∣x−1∣+6=0(\mathrm{x}-1)^{2}-5|\mathrm{x}-1|+6=0, is:

  1. Option A:

    44

    Correct
  2. Option B:

    33

  3. Option C:

    11

  4. Option D:

    55

Answer: A

Step-by-step solution

Let ∣x−1∣=t|x-1|=t

t2−5t+6=0\mathrm{t}^{2}-5 \mathrm{t}+6=0

t=2&t=3\mathrm{t}=2 \& \mathrm{t}=3

∣x−1∣=2&∣x−1∣=3|x-1|=2 \&|x-1|=3

x−1±2&x−1=±3\mathrm{x}-1 \pm 2 \& \mathrm{x}-1= \pm 3

x=1±2&x=1±3\mathrm{x}=1 \pm 2 \& \mathrm{x}=1 \pm 3

∴ root =3,−1,4,−2=3,-1,4,-2

∴ Sum of root =3+(−1)+4+(−2)=4=3+(-1)+4+(-2)=4.

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Quadratic Equations
Topic
Nature of Roots of Quadratic Equation
The sum of all the roots of the equation ( x -1) 2 -5 x -1 +6=0 , is: | JEE Main 2026 PYQ with Solution · DhiX AI