Chemistry · d and f Block Elements

JEE Main 2024 — 5 April, Shift 1 — Question 80

The spin only magnetic moment value of the ion among $\mathrm{Ti}^{2+}, \mathrm{V}^{2+}, \mathrm{Co}^{3+}$ and $\mathrm{Cr}^{2+}$ , that acts as strong oxidising agent in aqueous solution is $\qquad$ BM (Near integer). (Given atomic numbers : Ti : 22, V : 23, Cr : 24, Co : 27)

Answer: 5

Numerical answer — enter this value.

Step-by-step solution

Strong oxidising agent $=\mathrm{Co}^{+3}$

No. of unpaired $\mathrm{e}^{-}$ in $\mathrm{Co}^{+3}\left[3 \mathrm{~d}^{6}\right]=4$

Hence $\mu=\sqrt{\mathrm{n}(\mathrm{n}+2)}=\sqrt{24} \mathrm{BM}$

Nearest integer $=5$

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Exam: JEE Main 2024
Paper: 5 April, Shift 1
Subject: Chemistry
Chapter: d and f Block Elements
Topic: Introduction and Properties of Transition Elements

The metal that shows highest and maximum number of oxidation state is:

Answer: 5

Step-by-step solution

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