Physics · Current Electricity

JEE Main 2024 — 5 April, Shift 2 — Question 49

The ratio of heat dissipated per second through the resistance $5 \Omega$ and $10 \Omega$ in the circuit given below is :

Question figure

Option A:
$1: 2$
Option B:
$2: 1$
Correct
Option C:
$4: 1$
Option D:
$1: 1$

Answer: B

Step-by-step solution

The 5 $\Omega$ and 10 $\Omega$ resistors are connected in parallel, hence the same voltage $V$ appears across both.

P=\frac{V^2}{R}

\frac{P_{5}}{P_{10}} =\frac{V^2/5}{V^2/10} =\frac{10}{5} =2

P_{5\Omega}:P_{10\Omega}=2:1

Solution figure

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 5 April, Shift 2
Subject: Physics
Chapter: Current Electricity
Topic: Heating Effects of Current and Thermal Powe

The ratio of heat dissipated per second through the resistance 5 Ω… | JEE Main 2024 PYQ with Solution · DhiX AI