Physics · Atomic Physics

JEE Main 2024 — 27 January, Shift 1 — Question 38

The radius of third stationary orbit of electron for Bohr's atom is R . The radius of fourth stationary orbit will be:

Option A:
$\frac{4}{3} R$
Option B:
$\frac{16}{9} R$
Correct
Option C:
$\frac{3}{4} R$
Option D:
$\frac{9}{16} R$

Answer: B

Step-by-step solution

$r \propto \frac{n^{2}}{Z}$

$\frac{\mathrm{r}_{4}}{\mathrm{r}_{3}}=\frac{4^{2}}{3^{2}}$

$\mathrm{r}_{4}=\frac{16}{9} \mathrm{R}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 27 January, Shift 1
Subject: Physics
Chapter: Atomic Physics
Topic: Rutherford's and Bohr's Model of Atom

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