Mathematics · Permutations and Combinations

JEE Main 2024 — 8 April, Shift 2 — Question 5

The number of ways five alphabets can be chosen from the alphabets of the word MATHEMATICS, where the chosen alphabets are not necessarily distinct, is equal to :

  1. Option A:

    175

  2. Option B:

    181

  3. Option C:

    177

  4. Option D:

    179

    Correct

Answer: D

Step-by-step solution

AA, MM, TT, H, I, C, S, E

(1) All distinct 8C5→56{ }^{8} \mathrm{C}_{5} \rightarrow 56

(2) 2 same, 3 different 3C1×7C3→105{ }^{3} \mathrm{C}_{1} \times{ }^{7} \mathrm{C}_{3} \rightarrow 105

(3) 2 same Ist I^{\text {st }} kind, 2 same 2nd 2^{\text {nd }} kind, 1 different 3C2×6C1→18{ }^{3} \mathrm{C}_{2} \times{ }^{6} \mathrm{C}_{1} \rightarrow 18

Total →179\rightarrow 179

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Permutations and Combinations
Topic
Combinations
The number of ways five alphabets can be chosen from the alphabets of… | JEE Main 2024 PYQ with Solution · DhiX AI