Mathematics · Limits, Continuity and Differentiability

JEE Main 2026 — 2 April, Evening Shift — Question 47

The number of points in the interval [2, 4], at which the function f(x)=[x2−x−12]\mathrm{f(x)} = \left[\mathrm{x}^{2} - \mathrm{x} - \frac{1}{2}\right], where [·] denotes the greatest integer function, is discontinuous, is

Answer: 10

Numerical answer — enter this value.

Step-by-step solution

In x∈[2,4]\mathrm{x} \in[2,4], range of x2−x−12\mathrm{x}^{2}-\mathrm{x}-\frac{1}{2} is [1.5, 11.5] f(x)\mathrm{f}(\mathrm{x}) is discontinuous at points where x2−x−12\mathrm{x}^{2}-\mathrm{x}-\frac{1}{2} becomes integers. ∴ Integral values of x2−x−12\mathrm{x}^{2}-\mathrm{x}-\frac{1}{2} are 2,3,4,5,6,7,8,9,10,112,3,4,5,6,7, 8,9,10,11 ∴ Number of points where is discontinuous is 10

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Limits, Continuity and Differentiability
Topic
Continuity
The number of points in the interval [2, 4], at which the function… | JEE Main 2026 PYQ with Solution · DhiX AI