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Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Main 2024 — 5 April, Shift 2 — Question 74

The number of moles of methane required to produce 11 g11\,\text{g} of CO2(g)\mathrm{CO_2(g)} on complete combustion is _____\_\_\_\_\_. (Given: molar mass of methane =16 g mol−1= 16\,\text{g mol}^{-1}).

  1. Option A:

    0.75

  2. Option B:

    0.25

    Correct
  3. Option C:

    0.35

  4. Option D:

    0.5

Answer: B

Step-by-step solution

Complete combustion of methane: CH4(g)+2O2(g)→CO2(g)+2H2O(l)\mathrm{CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l)}

From the balanced equation,

1 mol   of   CH4→1 mol   of   CO21\,\text{mol \;of\; } \mathrm{CH_4} \rightarrow 1\,\text{mol \;of\; } \mathrm{CO_2}

Given mass of CO2=11 g\mathrm{CO_2} = 11\,\text{g}

Molar mass of CO2=44 g mol−1\mathrm{CO_2} = 44\,\text{g mol}^{-1}

Moles   of   CO2=1144=0.25 mol\text{Moles \;of\; } \mathrm{CO_2} = \frac{11}{44} = 0.25\,\text{mol}

Hence, moles of methane required =0.25 mol= 0.25\,\text{mol}.

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
5 April, Shift 2
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic
Chemical Equations, Stoichiometry and Limiting Reagent
The number of moles of methane required to produce 11\, g of CO 2(g)… | JEE Main 2024 PYQ with Solution · DhiX AI